No subject

********
virtual void vtkRenderer::Render (
 )  [virtual]

Create an image. This is a superclass method which will in turn call the
DeviceRender method of Subclasses of
vtkRenderer<http://www.vtk.org/doc/nightly/html/classvtkRenderer.html>


virtual void vtkRenderWindow::Render (
 )  [virtual]

Ask each renderer owned by this RenderWindow to render its image and
synchronize this process.

Implements vtkWindow<http://www.vtk.org/doc/nightly/html/classvtkWindow.html#acb783e66948656035da1bc0bf747c13a>
.

Reimplemented in
vtkXMesaRenderWindow<http://www.vtk.org/doc/nightly/html/classvtkXMesaRenderWindow.html#abb3258748e55ad41f3d6a6c4b145814c>,
and vtkXOpenGLRenderWindow<http://www.vtk.org/doc/nightly/html/classvtkXOpenGLRenderWindow.html#a33183ba56fc43126a34d2d82b1289988>
.

 ********

My RenderWindow has only one Renderer.
So, RenderWindow->Render() should be the same as Renderer->Render(),
according to the documentation...




> I was calling Render() on the Renderer - I changed to calling Render()
> on the RenderWindow and it behaves as I would expect.
>
> This is the kind of thing that seems very confusing...
>
> Thanks,
>
> David
> _______________________________________________
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I had the same problem! Calling Render() on the Renderer should work...<br>=
<br>From Documentation:<br><br>********<br><table class=3D"memname"><tbody>=
<tr><td class=3D"memname">virtual void vtkRenderer::Render </td>
          <td>(</td>
          <td class=3D"paramname"><br></td>
          <td>=A0)=A0</td>
          <td><code> [virtual]</code></td>
        </tr>
      </tbody></table>

<div class=3D"memdoc">
<p>Create an image. This is a superclass method which will in turn call the=
 DeviceRender method of Subclasses of <a class=3D"el" href=3D"http://www.vt=
k.org/doc/nightly/html/classvtkRenderer.html" title=3D"abstract specificati=
on for renderers">vtkRenderer</a></p>
<p><br></p><table class=3D"memname"><tbody><tr><td class=3D"memname">virtua=
l void vtkRenderWindow::Render </td>
          <td>(</td>
          <td class=3D"paramname"><br></td>
          <td>=A0)=A0</td>
          <td><code> [virtual]</code></td>
        </tr>
      </tbody></table>

<div class=3D"memdoc">
<p>Ask each renderer owned by this RenderWindow to render its image and syn=
chronize this process. </p>

<p>Implements <a class=3D"el" href=3D"http://www.vtk.org/doc/nightly/html/c=
lassvtkWindow.html#acb783e66948656035da1bc0bf747c13a">vtkWindow</a>.</p>

<p>Reimplemented in <a class=3D"el" href=3D"http://www.vtk.org/doc/nightly/=
html/classvtkXMesaRenderWindow.html#abb3258748e55ad41f3d6a6c4b145814c">vtkX=
MesaRenderWindow</a>, and <a class=3D"el" href=3D"http://www.vtk.org/doc/ni=
ghtly/html/classvtkXOpenGLRenderWindow.html#a33183ba56fc43126a34d2d82b12899=
88">vtkXOpenGLRenderWindow</a>.</p>


</div><p> </p>

</div>********<br><br>My RenderWindow has only one Renderer. <br>So, Render=
Window-&gt;Render() should be the same as Renderer-&gt;Render(), according =
to the documentation...<br><br><br><br><div class=3D"gmail_quote"><blockquo=
te class=3D"gmail_quote" style=3D"border-left: 1px solid rgb(204, 204, 204)=
; margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
<div class=3D"im">
<br>
</div>I was calling Render() on the Renderer - I changed to calling Render(=
)<br>
on the RenderWindow and it behaves as I would expect.<br>
<br>
This is the kind of thing that seems very confusing...<br>
<div><div class=3D"h5"><br>
Thanks,<br>
<br>
David<br>
_______________________________________________<br>
Powered by <a href=3D"http://www.kitware.com" target=3D"_blank">www.kitware=
.com</a><br>
<br>
Visit other Kitware open-source projects at <a href=3D"http://www.kitware.c=
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nsource/opensource.html</a><br>
<br>
Please keep messages on-topic and check the VTK FAQ at: <a href=3D"http://w=
ww.vtk.org/Wiki/VTK_FAQ" target=3D"_blank">http://www.vtk.org/Wiki/VTK_FAQ<=
/a><br>
<br>
Follow this link to subscribe/unsubscribe:<br>
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</div></div></blockquote><br></div><br>

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